MISC
Maths Problems dated 03 Nov 2021
Problem No 01
In the given figure APB and AQB are two semi circle. (Given)
Perimeter of the given shape will be equal to
= Circumference of half semi circle (APB) + Circumference of quarter semicircle AQO + QO RADIUS + OB RADIUS
= ( PI * R ) + (0.5 * PI * R) + R + R
But this perimeter is given equal to the 47 cm.
Hence,
( PI * R ) + (0.5 * PI * R) + R + R = 47 cm
R * ( 22/7 + 11/7 + 1 + 1 ) = 47 CM
R * ( 47/7) = 47 CM
It implies that R = 7 cm
Area of Shaded Region
Area of total Circle - Area of Quarter CIrcle
(PI * R * R ) - (0.25 * PI * R* R) = (0.75 * PI * R* R)
= 0.75 * 22/7 * 7 * 7 = 115.50 CM2 ANS
It seems that answer given is incorrect.
Problem No 02
Hence the correct answer is C 7 : 1 .
Problem No 03
Thank you.
Feel free to write your comments and suggestions in the comment box given below.
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