Exercise 3E R S Agarwal
Problem No 01
Chair = x
Tables = y
5 x + 4 y = 5600 ..... 1
4 x + 3 y = 4340 ....... 2
1 * 4 & 2 * 5
20x + 16 y = 22400.......... a
20x + 15y = 21700............b
a-b
y = 700
5x + 2800 = 5600
5x = 2800
x = 560 Ans
Problem No 02
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Maths Problems dated 03 Nov 2021
Area of Shaded Region
Chapter 02 Polynomials
Problem No 01 :- Find the Zeros of the Polynomials and verify the relationship between the zeros and coefficients :-
x2 + 7x + 12
To find the zeros of polynomial, It should be equated to zero first
Hence,
x2 + 7x + 12 = 0
Or, x2 + 4x + 3x + 12 = 0
Or, x (x + 4)+ 3 (x + 4 ) = 0
Or, (x + 3) * (x + 4 ) = 0
It implies that x = - 3 & -4 Ans ............................................... (1)
Comparing the Given Eqn with Stnd Eqn i.e. ax2 + bx + c = 0
We Get, a=1 , b = 7 & c = 12
α + β = -3 + ( - 4) = - 7................................... (2)
-b /a = -7 / 1 = -7 .............................................(3)
Also α * β = -3 * -4 = 12 .................................(4)
c / a = 12 / 1 ......................................................(5)
From (2), (3) (4) & (5) relation between the zeros and coefficients can be verified.