Showing posts with label CLASS 10 MATHS. Show all posts
Showing posts with label CLASS 10 MATHS. Show all posts
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Problems dated Nov 05 2021

posted on , by UDBHAV

Problems Dated Nov 05 2021. Problem No 09 First Number = x Second Number =y Case 1 (x+2)/(y+2) = 1/2Case 2 (x-4)/(y-4) = 5/11From 1 2x - y = -2 ...... 3 from 2 11x - 5y = 24 .... 4 Multiplying Eqn 1 by 5 10 x - 5y = -10   .......5Eqn 4 -Eqn 5 11x - 5y -10 x + 5y = 24 + 10 x = 34 From Eqn 1 2 (34) - y = ...

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Linear Eqn in Two Variables.

posted on , by UDBHAV

 Exercise 3E R S Agarwal Problem No 01 Chair = x Tables = y 5 x + 4 y = 5600 ..... 1 4 x + 3 y = 4340 ....... 2 1 * 4  &  2 * 5 20x + 16 y = 22400.......... a 20x + 15y = 21700............b a-b y = 7005x + 2800 = 5600 5x = 2800 x = 560 Ans Problem No 02 To read More Such Posts related ...

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Maths Problems dated 03 Nov 2021

posted on , by UDBHAV

 MISCMaths Problems dated 03 Nov 2021Problem No 01In the given figure APB and AQB are two semi circle. (Given) Perimeter of the given shape will be equal to = Circumference of half semi circle (APB) + Circumference of quarter semicircle AQO + QO RADIUS + OB RADIUS = ( PI * R ) + (0.5 * PI * R) + R + R But this perimeter is given equal to the 47 cm.Hence, ( ...

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Chapter 02 Part B Polynomials

posted on , by UDBHAV

CHAPTER O2 PART B POLYNOMIALSIn the Figure given below, find the number of zeroes in each case.  How to Calculate Zeroes, when the Graph of a Polynomial has been given ? The Zeroes of a Polynomial indicates the values of 'x' at which the value of polynomial p(x) becomes zero. Hence In a Grapgh plotted for the Polynomial, the points at which the value of Polynomials ...

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