In this question, Some basic formulas were required to be applied and than compared with the end results. The question can be seen below :- The answer is as follows :- Please comment below, if you like the answer.&nbs ...
Solution 1. Let us suppose one Part is x and other part is y. As per given condition(4/7)x = (2/5)yOr 10x = 7y Or x = (7/10) y As x and Y are two parts of number so their sum will be equal to that number. Hence x + y = 34or (7/10) y + y = 34 Or 17 y = 340 Or y = 20 And x = 34-20 = 14Hence correct option is d. Solution ...
Problem Dated 15 Nov 2021. Class 11 PhysicsChapter No 03 Question No 3.8 3.8 On a two-lane road, car A is travelling with a speed of 36 km h–1. Two cars B and C approach car A in opposite directions with a speed of 54 km h–1 each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What minimum acceleration ...
Problems dated Nov 05 2021
Problems Dated Nov 05 2021. Problem No 09 First Number = x Second Number =y Case 1 (x+2)/(y+2) = 1/2Case 2 (x-4)/(y-4) = 5/11From 1 2x - y = -2 ...... 3 from 2 11x - 5y = 24 .... 4 Multiplying Eqn 1 by 5 10 x - 5y = -10 .......5Eqn 4 -Eqn 5 11x - 5y -10 x + 5y = 24 + 10 x = 34 From Eqn 1 2 (34) - y = ...
Linear Eqn in Two Variables.
Exercise 3E R S Agarwal Problem No 01 Chair = x Tables = y 5 x + 4 y = 5600 ..... 1 4 x + 3 y = 4340 ....... 2 1 * 4 & 2 * 5 20x + 16 y = 22400.......... a 20x + 15y = 21700............b a-b y = 7005x + 2800 = 5600 5x = 2800 x = 560 Ans Problem No 02 To read More Such Posts related ...
Maths Problems dated 03 Nov 2021
MISCMaths Problems dated 03 Nov 2021Problem No 01In the given figure APB and AQB are two semi circle. (Given) Perimeter of the given shape will be equal to = Circumference of half semi circle (APB) + Circumference of quarter semicircle AQO + QO RADIUS + OB RADIUS = ( PI * R ) + (0.5 * PI * R) + R + R But this perimeter is given equal to the 47 cm.Hence, ( ...
CHAPTER O2 PART B POLYNOMIALSIn the Figure given below, find the number of zeroes in each case. How to Calculate Zeroes, when the Graph of a Polynomial has been given ? The Zeroes of a Polynomial indicates the values of 'x' at which the value of polynomial p(x) becomes zero. Hence In a Grapgh plotted for the Polynomial, the points at which the value of Polynomials ...
Chapter 02 Polynomials
Chapter 02 Polynomials Problem No 01 :- Find the Zeros of the Polynomials and verify the relationship between the zeros and coefficients :-x2 + 7x + 12To find the zeros of polynomial, It should be equated to zero firstHence,x2 + 7x + 12 = 0Or, x2 + 4x + 3x + 12 = 0Or, x (x + 4)+ 3 (x + 4 ) = 0Or, (x + 3) * (x + 4 ) = 0It implies that x = - 3 & -4 Ans ............................................... (1)Comparing the Given Eqn with Stnd Eqn i.e. ax2 + bx + c = 0We Get, a=1 , b = 7 & ...
CLASS 10 MATHEMATICS
CLASS 10 MATHEMATICSWelcome All, In this Section, a collection of problems have been presented from various Books of CBSE Mathematics Class 10. Problems can be seen by clicking on the list of chapters given below :- Real NumbersPolynomialsLinear Equation in Two VariablesTrianglesTrigonometric Ratios. T-Ratios of some Particular Angles. Trigonometric Ratios of Complementary Angles. Trigonometric Identities. Mean, Median, Mode of Grouped Data, Cumulative ...
Class 10 Area Answer:- As per the DiagramEC = BC (Radius in Sector BGEC) Hence EC = 7 Cm. DE = 4 cm Given DC = DC + EC = 4 CM + 7 CM = 11 cm Area of trapezium ABCD = (1/2) *( Sum Of ||el sides) * (Height)= (1/2) * (AB+DC) *(BF) =(1/2) * (7 cm + 11 cm ) * (3.5 cm ) = 0.5 * 18 cm * 3.5 cm = 9 cm * 3.5 cm = 31.50 cm2 Area ...
Numericals on Hydrostatic Forces on Surfaces.
Hydrostatic Forces on SurfacesNumerical No. 1 Numerical No 02 ...
Plumbing Plumbing notes based on SP-35 1987 are as follows :- 1. General Plumbing System includes water supply and distributing pipes plumbing fixtures for the use in water supplysanitary drainage system to carry the wastes Anti-siphonage system which carry only the air for the purpose of ventilation Storm water drainage ...